The information in the RS batch, together with the information in the VC batch, specify the time characteristics of the excitation. The excitation $\mathbf{b}(t)$ is assumed in the form of a product (skleronomic) vector $\mathbf{b}_0$ and a scalar function of time $f(t),$ i.e., $$\mathbf{b}(t) = \mathbf{b}_0f(t).$$ The vector $\mathbf{b}_0$ contains axial components of amplitudes, either

• nodal forces $\mathbf{R}$ in all nodes of the mesh $\mathbf{R}_0=\mathbf{b}_0$ for $\mathtt{KKIN}=0,$ or
• nodal displacements $\mathbf{u}$ in all nodes of the mesh $\mathbf{u}_0=\mathbf{b}_0$ for $\mathtt{KKIN}=1.$

The time function $f(t)$ is designed in the form of product of the partial sum of the Fourier series and a polynomial, i.e., \begin{align} f(t) &= F(t)P(t),\\ F(t) &= \sum_{k=1}^\mathtt{NFOUR}\left[A_k\cos(\omega_kt)+B_k\sin(\omega_kt)\right],\\ P(t) &= e^{at}\left(C_1t^{\mathtt{NPOL}-1}+C_2t^{\mathtt{NPOL}-2}+\dots+C_{\mathtt{NPOL}-1}t+C_\mathtt{NPOL}\right). \end{align}

Note
$\mathtt{NFOUR}=0$ implicates $F(t)=1,$ $\mathtt{NPOL}=0$ implicates $P(t)=1.$

Note
If the excitation acts only on a few nodes, it is convenient to use the condensed notation for $\mathbf{b}_0.$
If the excitation is distributed to many nodes, or if it is a subject of calculation or measurement, it may be advantageous to provide $\mathbf{b}_0$ in the special file name.1 (or name.2).

Note for $\mathtt{KFEAT}=3$
The zero force component in $\mathbf{R}_0=\mathbf{b}_0$ means that the excitation in that place and direction is zero. The zero displacement component in $\mathbf{u}_0=\mathbf{b}_0$ means the absence of kinematic excitation in that place and direction; in no way does it represent a > prescribed zero displacement.

Note for $\mathtt{KFEAT}=11$
The intervals $(t_{Li},t_{Ui}),$ $i=1,2,\dots,$ defined by the even number of ascending time levels $t_{L1},$ $t_{U1},$ $t_{L2},$ $t_{U2},\dots~[\text{s}]$ let the continuous-in-time excitation $\mathbf{b}(t)$ not be activated in intervals $(t_{Li},t_{Ui}),$ $i=1,2,\dots.$ As soon as the time $t$ reaches the value $t=t_{Ui},$ the program sets $t_0=t_{Ui}$ and for the next interval $(t_{Ui},t_{Li+1})$ it holds the excitement again as $$\mathbf{b}(t) = \mathbf{b}_0f(t-t_{Ui}) = \mathbf{b}_0f(t-t_0) = \mathbf{b}_0(t)f(t).$$