en:example:nlin:2:2
Table of Contents
Triangles, BEAM4G2
Problem
Mesh
Boundary conditions
$u=v=0$ at node 11
$v=0$ at node 27
Solution
The unit end force is replaced with the equivalent surface traction as $$q_x=\frac{-1}{0.01\times 0.02}=-5000\text{ Pa},\quad q_y=0\text{ Pa}.$$
The initial stress matrix is then computed from the stress field obtained by the standard linear analysis.
- beam56g2.bat
rmd2 beam4g2.i1 rpd2 beam4g2.i2 srh2 beam4g2.i3 fefs beam4g2.i4 geo2 beam4g2.iG heig beam4g2.iE stab beam4g2.iS
Input
- beam4g2.i1
; NELEM NNOD ITED ... KSS IP 8 27 4 6*0 -1 ; CRIT SCALE THDEF RP 1.01 1 0.01 XY N 1:10 X 2*0 2*0.25 2*0.5 2*0.75 2*1 Y 5*(0 0.02) EL E 1:8 N =P 1 3 2 =P =Q 12 13 11 =Q =R 3 4 2 =R =S 15 14 13 =S =2P =4Q =2R =4S =4P =8Q =4R =8S =6P =12Q =6R =12S EN EN
- beam4g2.i2
; KREST IP 1 ; E α ν ρ MP 1 T 1 V 2e11 0 0.3 0 SV 1 T 9 V -5000 0 0 ; Fx = -1 N AS 1 /M 1 /B 0 N 11 /B 0 C 2 N 27 /S 1 E 8 S2 EN EN
- beam4g2.i3
; KREST IP 1 EN EN
- beam4g2.i4
; KREST IP 1 EN EN
- beam4g2.iG
; ILC IP 1 EN EN
- beam4g2.iE
; KREST NROOT NITERX KTPR KEVP IP 1 1 0 0 1 EN EN
- beam4g2.iS
IP 1 EN EN
Output
- beam4g2.oS
IP 1 EN EN LOADING PARAMETERS 0.140350E+04 * END OF STAB * TOTAL CPU: 00:00:00
en/example/nlin/2/2.txt · Last modified: 2022-02-22 14:29 by Petr Pařík