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Finite Element Analysis in Structural Mechanics

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en:example:heat:2:4

Table of Contents

Semi-loofs, BEAM61T2

Problem

Mesh

element type nodes
1 61 1 2 4 3 11 13 14 12 
2 61 3 4 6 5 14 16 17 15
3 61 5 6 8 7 17 19 20 18
4 61 7 8 10 9 20 22 23 21

Solution

beam61t2.bat
xrm3 beam61t2.i1
xrpd beam61t2.iB
xt3t beam61t2

Input

beam61t2.i1
;  NELEM NNOD ITED
IP   4    23   61
;  CRIT SCALE THDEF
RP 1.01   1    0.01
XY N 1:10 X 2*0 2*0.25 2*0.5 2*0.75 2*1
          Y 5*(0 0.02)
          Z 10*0
EL E 1:4 N =A 1 2 4 3 =A =B 11 13 14 12 =B
           =2A =3B =4A =6B =6A =9B
EN
EN
beam61t2.iB
;  KREST 0 KOUT INT3 NSAX NSTEPX KSU
IP   1   0   2    0   10   1000   0
;  TIMS ERAL EDIF TOL DTRUN
RP   0  1e-5  0.1 0.1  3600
MP 1 T 1 V 20 3e6
IV 1 T 5 V 0 0.1
LV 1 T 1 I 1 V 30 10 V 2*-20 ; x = 0 m, To = -20 °C
LV 2 T 1 I 1 V 30 10 V 2*25  ; x = 1 m, To =  25 °C
AV 1 T 6 N 1 1 1 V 4*0       ; KAPPR KAUTO KPRED
GV 1 T 1 V 46*25             ; initial conditions

AS 1 /M 1 /A 1 /G 1
  /L 1 E 1 L1
  /L 2 E 4 L3
  /R 720000 36000 1 ; total time = 200 h, initial time step = 10 h

EN
EN

Output

beam61t2.STR
#  163    0.72000E+06
$TEMPERATURE
      1 -0.1160E+02  0.0000E+00  0.0000E+00
      2 -0.1160E+02  0.3855-307  0.0000E+00
      3 -0.8457E+01  0.3336-307  0.0000E+00
      4 -0.8457E+01  0.9116-307  0.0000E+00
      5 -0.5347E+01  0.0000E+00  0.0000E+00
      6 -0.5347E+01  0.0000E+00  0.0000E+00
      7 -0.2269E+01  0.4070-307  0.0000E+00
      8 -0.2269E+01  0.0000E+00  0.0000E+00
      9  0.7758E+00  0.0000E+00  0.0000E+00
     10  0.7758E+00  0.7914-307  0.0000E+00
     11 -0.1160E+02  0.3235-307  0.0000E+00
     12 -0.1002E+02  0.0000E+00  0.0000E+00
     13 -0.1002E+02  0.0000E+00  0.0000E+00
     14 -0.8457E+01  0.3331-307  0.0000E+00
     15 -0.6898E+01  0.0000E+00  0.0000E+00
     16 -0.6898E+01  0.0000E+00  0.0000E+00
     17 -0.5347E+01  0.0000E+00  0.0000E+00
     18 -0.3803E+01  0.0000E+00  0.0000E+00
     19 -0.3803E+01  0.0000E+00  0.0000E+00
     20 -0.2269E+01  0.0000E+00  0.0000E+00
     21 -0.7422E+00 -0.3006-307  0.0000E+00
     22 -0.7422E+00  0.0000E+00  0.0000E+00
     23  0.7758E+00  0.2319-307  0.0000E+00
en/example/heat/2/4.txt · Last modified: 2022-03-15 08:28 by Petr Pařík